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LeetCode--Linked List Cycle II
Given a linked list, return the node where the cycle begins. If there is no cycle, return null
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Follow up:
Can you solve it without using extra space?
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *detectCycle(ListNode *head) { if(head==NULL || head->next==NULL) return NULL; ListNode* slow = head; ListNode* fast = head; while(fast!=NULL && fast->next!=NULL) { slow = slow->next; fast = fast->next; fast = fast->next; if(slow == fast) break; } if(slow == fast) { slow = head; while(slow!=fast) { slow = slow->next; fast = fast->next; } return slow; } return NULL; } };
LeetCode--Linked List Cycle II
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