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[hdu4763]next数组的应用

http://acm.hdu.edu.cn/showproblem.php?pid=4763

题目大意:给一个字符串,判断是否可以写成ABACA,B、C表示长度大于等于0的字符串。

方法:ans = next[len]如果小于等于len/3,则ans是最大可能的答案,否则ans = next[ans] 要继续往前走,直到ans <= len/3, 然后枚举从2*ans位置枚举到len - ans,看是否存在某个位置j, 使得next[j] = ans,当然这里也有一个往前走的过程(如果next[j]一开始大于ans),具体见代码:

 1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <cmath> 5 #include <algorithm> 6 #include <map> 7 #include <vector> 8 #include <stack> 9 #include <string>10 #include <ctime>11 #include <queue>12 #define mem0(a) memset(a, 0, sizeof(a))13 #define mem(a, b) memset(a, b, sizeof(a))14 #define lson l, m, rt << 115 #define rson m + 1, r, rt << 1 | 116 #define eps 0.000000117 #define lowbit(x) ((x) & -(x))18 #define memc(a, b) memcpy(a, b, sizeof(b))19 #define x_x(a) ((a) * (a))20 #define LL long long21 #define DB double22 #define pi 3.1415926535923 #define MD 1000000724 #define INF (int)1e925 #define max(a, b) ((a) > (b)? (a) : (b))26 using namespace std;27 char str[1200000];28 int next[1200000];29 void getNext()30 {31         next[0] = next[1] = 0;32         for(int i = 1; str[i]; i++) {33                 int j = next[i];34                 while(j && str[i] != str[j]) j = next[j];35                 next[i + 1] = str[i] == str[j]? j + 1 : 0;36         }37 }38 int solve()39 {40         int len = strlen(str), ans = next[len], F = 0;41         while(ans * 3 > len) ans = next[ans];42         while(ans) {43                 for(int i = ans * 2; i <= len - ans; i++) {44                         int j = next[i];45                         while(j > ans) j = next[j];46                         if(j == ans) {47                                 F = 1;48                                 break;49                         }50                 }51                 if(F) break;52                 ans = next[ans];53         }54         return ans;55 }56 int main()57 {58         //freopen("input.txt", "r", stdin);59         int T;60         cin>> T;61         for(int i = 1; i <= T; i++) {62                 scanf("%s", str);63                 getNext();64                 cout<< solve()<< endl;65         }66         return 0;67 }
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[hdu4763]next数组的应用