例3-5

num=5*[1 5 6];den=[1 6 10 8];

%函数阶跃响应

sys0=tf(num,den)

step(sys0)

%零极点形式的传递函数

[z p k]=tf2zp(num,den);

sys=zpk(z,p,k)

%部分分式展开

[r p k]=residue(num,[den 0]);

%拉普拉斯反变换

syms s

f=ilaplace(sum(r./(s-p)));

temp=simple(f);

disp(‘时域方程‘)

temp

sys0 =

5 s^2 + 25 s + 30

----------------------

s^3 + 6 s^2 + 10 s + 8

Continuous-time transfer function.

sys =

5 (s+3) (s+2)

--------------------

(s+4) (s^2 + 2s + 2)

Continuous-time zero/pole/gain model.

时域方程

temp =

(exp(-t)*sin(t))/2 - (7*exp(-t)*cos(t))/2 - exp(-4*t)/4 + 15/4

自动控制基础MATLAB 2