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[LeetCode] Spiral Matrix

Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.

For example, Given the following matrix:

[ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ]]

You should return [1,2,3,6,9,8,7,4,5].

class Solution {public:    vector<int> spiralOrder(vector<vector<int> > &matrix) {        int m = matrix.size();//原矩阵m行n列        vector<int> res;        if(m==0)            return res;        int n = matrix[0].size();                                int rowStart=0,rowEnd=m-1,colStart=0,colEnd=n-1;               int j=colStart,i=rowStart ;        while(1)        {                        for(j = colStart;j<=colEnd;j++)            {                res.push_back(matrix[i][j]);            }            j = j-1;            if(res.size()==m*n)                break;            rowStart++;            j = colEnd;            for(i=rowStart;i<=rowEnd;i++)            {                res.push_back(matrix[i][j]);            }            colEnd--;            i = rowEnd;            for(j=colEnd;j>=colStart;j--)            {                res.push_back(matrix[i][j]);            }            j = j+1;            if(res.size()==m*n)                break;            rowEnd--;            j=colStart;            for(i = rowEnd;i>=rowStart;i--)            {                res.push_back(matrix[i][j]);            }            colStart++;            i = rowStart;        }//end while    return res;    }};

 

[LeetCode] Spiral Matrix