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比赛之树状数组题
1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <algorithm> 5 using namespace std; 6 #define F first 7 #define S second 8 #define MP(a,b) make_pair( make_pair(a,b) , -1 ) 9 typedef pair< pair<int,int> , int> coder ;10 const int maxn = 300010 ;11 const int N = 100000 ;12 13 int sum[N+1] , ans[maxn] ;14 coder p[maxn] ;15 16 inline int lowbit(int x){17 return x & -x ;18 }19 void update(int x) {20 for(; x<=N; x+=lowbit(x)) sum[x]++ ;21 }22 int query(int x) {23 int ret = 0 ;24 for(; x>0 ; x-=lowbit(x)) ret += sum[x] ;25 return ret ;26 }27 28 int main()29 {30 int n ;31 scanf("%d", &n);32 for(int i=1; i<=n; i++)33 scanf("%d%d", &p[i].F.F , &p[i].F.S) , p[i].S = i ;34 sort(p+1 , p+1+n) ;35 int y = 1;36 37 for(int i=1; i<=n; i++) {38 int u = p[i].S ;39 while(y<i && p[y].F.F < p[i].F.F) {40 update(p[y++].F.S) ;41 }42 ans[u] += query(p[i].F.S) ;43 if(y < i) {44 ans[u] += lower_bound(p+y , p+i , MP(p[i].F.F , p[i].F.S)) - p - y ;45 }46 }47 48 for(int i=1; i<=n; i++)49 printf("%d\n" , ans[i]) ;50 51 return 0;52 }
Description
Some of the more elite (and not-so-elite) coders around take part in a certain unnamed programming contest. In said contest, there are multiple types of competitions. Here, we consider the Open and High School competition types. For each type, each competitor receives a rating, an integer between 1 and 100000, inclusive. A coder‘s rating is based upon his or her level of performance in matches and is calculated using a complicated formula which, thankfully, you will not be asked to implement.
Although the Open and High School ratings for a coder who has participated in both competition types lately are usually close, this is not always the case. In particular, High School matches are more about speed, since many coders are able to solve all the problems, whereas Open matches require more thinking and there is a steeper curve in terms of problem difficulty.
Problem Statement
You are given N coders (1 ≤ N ≤ 300000), conveniently numbered from 1 to N. Each of these coders participates in both High School and Open matches. For each coder, you are also given an Open rating Ai and a High School rating Hi. Coder i is said to be better than coder j if and only if both of coder i‘s ratings are greater than or equal to coder j‘s corresponding ratings, with at least one being greater. For each coder i, determine how many coders coder i is better than.
Input Format
On the first line of input is a single integer N, as described above.
N lines then follow. Line i+1 contains two space-separated integers, Ai and Hi.
Output Format
Line i should contain the number of coders that coder i is better than.
Sample Input
81798 1832862 7001075 10891568 15572575 19841033 9501656 16491014 1473
Sample Output
60247151