RewardProblem DescriptionDandelion‘s uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his
https://www.u72.net/daima/vr3u.html - 2024-07-15 02:12:34 - 代码库RewardTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3854 Accepted Submission(s
https://www.u72.net/daima/vr57.html - 2024-07-15 02:17:58 - 代码库逃生Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 902 Accepted Submission(s): 2
https://www.u72.net/daima/vv9r.html - 2024-07-15 05:04:13 - 代码库Problem DescriptionRecently, scientists find that there is love between any of two people. For example, between A and B, if A don’t love B,
https://www.u72.net/daima/vkun.html - 2024-07-14 21:25:38 - 代码库John has n tasks to do. Unfortunately, the tasks are not independent and the execution of one task is only possible if other tasks have alre
https://www.u72.net/daima/05h9.html - 2024-08-29 11:56:33 - 代码库#include<stdio.h>#include<iostream>#include<string.h>#include<queue>#include<stack>#include<list>#include<stdlib.h>#include<algorithm>#inclu
https://www.u72.net/daima/rxnr.html - 2024-07-12 03:29:25 - 代码库Going from u to v or from v to u?Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 14566 Accepted: 3846DescriptionIn order to make t
https://www.u72.net/daima/76e8.html - 2024-07-25 19:00:18 - 代码库题目来源:http://acm.hdu.edu.cn/showproblem.php?pid=1285Problem Description有N个比赛队(1<=N<=500),编号依次为1,2,3,。。。。,N进行比赛,比赛结束后,裁判委
https://www.u72.net/daima/4kzv.html - 2024-09-04 06:55:37 - 代码库题目链接题意:对于一个序列a1,a2...an,我们可以计算出一个符号矩阵S,其中Sij为ai&#43;..&#43;aj的正负号。给出符号矩阵,要求输出一个对应的序列。思路:使用
https://www.u72.net/daima/60eu.html - 2024-07-24 12:12:35 - 代码库逃生Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1161 Accepted Submission(s):
https://www.u72.net/daima/4d00.html - 2024-07-22 01:04:45 - 代码库题意:给你n个点、m个关系,每个关系两个点u、v,表示u小于v,叫你输出任意一个序列保证满足所有给定的关系 例如:n=3 m=2 1 2 3
https://www.u72.net/daima/m35x.html - 2024-09-17 10:08:40 - 代码库先来看看ITopologicalOperator的成员:截图来自帮助文档:简要介绍下各个成员的汉语翻译:1、Boundary,边界,获取一个Geometry的边界;用法: ITopologicalOperat
https://www.u72.net/daima/e1zn.html - 2024-07-28 16:35:27 - 代码库Labeling BallsTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 11146 Accepted: 3192DescriptionWindy has N balls of distinct weights
https://www.u72.net/daima/8cc4.html - 2024-07-26 07:04:52 - 代码库【Description】 在大型过程的施工前,我们经常把整个工程分为若干个子工程,并把这些子工程编号为 1、2、…、N;这样划分之后,子工程之间就会有一些
https://www.u72.net/daima/nnhhu.html - 2024-09-19 21:26:31 - 代码库#include "stdafx.h"#include "stdio.h"#include "stdlib.h"#define MAX_VERTEX_NUM 11 //顶点的最大数#define INFINITY 32768
https://www.u72.net/daima/nkrn0.html - 2024-08-03 22:19:10 - 代码库Genealogical treeTime Limit: 1000MSMemory Limit: 65536KTotal Submissions: 2738Accepted: 1838Special Judge
https://www.u72.net/daima/nh64m.html - 2024-09-24 13:27:23 - 代码库题目链接POJ1128思路如果在A的边框上出现了字母B,就说明B在A的上方如果边框A在边框B的下方,就添加从A到B的一条有向边(题目要求从下到上输出)那么所求
https://www.u72.net/daima/nf0cw.html - 2024-10-07 16:21:39 - 代码库RewardTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4379 Accepted Submission(
https://www.u72.net/daima/nruva.html - 2024-08-09 08:13:52 - 代码库正向每次取最小并不能保证为最优解,反向建边每次取最大可得正解。代码:#include<iostream>#include<cstdio>#include<cmath>#include<map>#include<q
https://www.u72.net/daima/nd2h3.html - 2024-08-05 07:33:14 - 代码库DescriptionThe system of Martians‘ blood relations is confusing enough. Actually, Martians bud when they want and where they want. They gat
https://www.u72.net/daima/nbmf2.html - 2024-08-06 18:18:22 - 代码库