AsteroidsTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 14399 Accepted: 7836DescriptionBessie wants to navigate her spaceship thr
https://www.u72.net/daima/rkzd.html - 2024-07-11 18:42:01 - 代码库过山车Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 9745 Accepted Submission(s
https://www.u72.net/daima/rkcb.html - 2024-07-11 18:52:55 - 代码库Antenna PlacementTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 6438 Accepted: 3176看了别人的题解才过的。。。 渣啊。。最主要的是
https://www.u72.net/daima/sdce.html - 2024-07-12 21:21:39 - 代码库The Perfect StallHal BurchFarmer John completed his new barn just last week, complete with all the latest milking technology. Unfortunatel
https://www.u72.net/daima/2uc7.html - 2024-09-01 08:01:31 - 代码库N头牛,M个畜栏,每头牛只喜欢其中的某几个畜栏,但是一个畜栏只能有一只牛拥有,问最多可以有多少只牛拥有畜栏。 典型的指派型问题,用二分图匹
https://www.u72.net/daima/0d21.html - 2024-07-17 21:49:22 - 代码库AsteroidsTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 14399 Accepted: 7836DescriptionBessie wants to na
https://www.u72.net/daima/ndkwh.html - 2024-09-29 05:41:38 - 代码库N头牛,M个畜栏,每头牛仅仅喜欢当中的某几个畜栏,可是一个畜栏仅仅能有一仅仅牛拥有,问最多能够有多少仅仅牛拥有畜栏。 典型的指派型问
https://www.u72.net/daima/nrza1.html - 2024-10-12 21:11:38 - 代码库Problem DescriptionConsider a group of N students and P courses. Each student visits zero, one or more than one courses. Your task is to det
https://www.u72.net/daima/nd303.html - 2024-10-01 02:06:02 - 代码库Machine ScheduleTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5371 Accepted Su
https://www.u72.net/daima/rkd6.html - 2024-07-11 18:48:34 - 代码库题意:N个学生,P个课程,问能不能找到课程的P个匹配。思路:【早上睡醒了再写】代码: 1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #in
https://www.u72.net/daima/1r33.html - 2024-07-19 01:19:31 - 代码库过山车Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11520 Accepted Submission(s
https://www.u72.net/daima/nah43.html - 2024-07-30 07:54:49 - 代码库首先,最小路径覆盖=总节点数-最大匹配数。这个应该已经是路人皆知了。所谓最小路径覆盖。是指在一个有向图中。找出最少的几条路径。用它们来覆盖全
https://www.u72.net/daima/nzv4w.html - 2024-09-22 06:14:06 - 代码库题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3605EscapeTime Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Othe
https://www.u72.net/daima/ns64z.html - 2024-10-19 08:30:39 - 代码库题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=2063#include <iostream>#include <stdio.h>#include <string.h>using namespace std;int
https://www.u72.net/daima/nvffx.html - 2024-10-29 09:16:39 - 代码库传送门 把所有非障碍的相邻格子彼此连一条边,然后求二分图最大匹配,看 tot * 2 + k 是否等于 n * m 即可。但是连边不能重复,比如 a 格子 和 b 格子 相邻,
https://www.u72.net/daima/nnzh4.html - 2024-09-19 19:50:23 - 代码库原文:http://blog.csdn.net/dark_scope/article/details/8880547<em>匈牙利</em>算法是由<em>匈牙利</em>数学家Edmonds于1965
https://www.u72.net/daima/1vkr.html - 2024-08-30 16:33:47 - 代码库一开始还没看懂这个算法,后来看了陶叔去年的PPT的实例演示才弄懂用一个lx[]和ly[]来记录X和Y集合中点的权值,有个定理是 lx[i]+ly[j]==w[i][j](边权值)
https://www.u72.net/daima/k0vk.html - 2024-07-07 03:24:01 - 代码库The Perfect StallTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 17895 Accepted: 8143DescriptionFarmer John completed his new barn
https://www.u72.net/daima/rkr6.html - 2024-07-11 18:55:49 - 代码库1191: [HNOI2006]超级英雄HeroTime Limit: 10 Sec Memory Limit: 162 MBSubmit: 1804 Solved: 850[Submit][Status]Description现在电视台有一种节
https://www.u72.net/daima/2bwr.html - 2024-07-19 23:47:26 - 代码库联系人姓名由prefix / given name / middle name / family name / suffix组成。世界各地对于姓名显示的顺利是不同的。例如中国习惯是:family name &#4
https://www.u72.net/daima/6s7x.html - 2024-07-24 07:23:42 - 代码库