http://202.197.224.59/OnlineJudge2/index.php/Problem/read/id/1184

给定原字符串，和需要删掉的字符串集，然后输出删除后的字符串，如果长度变为0，输出LOSER。

考验编码能力  ！！

#include<cstdio>
#include<string>
#include<iostream>
using namespace std;
char ss[10][10]={"HATE","SHIT","LV","O","FUCK","UGLY","MM"};
int dit[10]={4,4,2,1,4,4,2};
string s;
string jiesu(string s)
{
    string s1="";
    for(int i=0;i<s.size();i++)
        if(s[i]!='#')
        s1+=s[i];
    return s1;
}
bool solve()
{
    int flag=0;
    for(int i=0;i<7;i++)
    {
        int t=-1;
        t=s.find(ss[i]);
        if(t!=-1)
        {
            flag=1;
            for(int j=t;j<t+dit[i];j++)
            s[j]='#';
        }
    }
    s=jiesu(s);
    return flag;
}
int main()
{
    while(cin>>s)
    {
        while(solve());
        if(s.size()) cout<<s<<endl;
        else cout<<"LOSER\n";
    }
    return 0;
}

XTU_1184 A Love Letter