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UVA 10183 How Many Fibs?

高精度推出大概600项fabi数,就包含了题目的数据范围,对于每组a,b,从1到600枚举res[i]即可

可以直接JAVA大数。我自己时套了C++高精度的版

JAVA 复制别人的

import java.math.BigInteger;import java.util.Scanner;public class Main {    public static void main(String[] args) {        Scanner cin = new Scanner(System.in);        BigInteger[] f = new BigInteger[600];        f[0] = new BigInteger("1");        f[1] = new BigInteger("2");        for(int i = 2; i < 600; i ++)            f[i] = f[i - 1].add(f[i - 2]);        for(;;)        {            BigInteger a, b;            int res = 0;            a = cin.nextBigInteger();            b = cin.nextBigInteger();            if(a.compareTo(BigInteger.ZERO) == 0 && b.compareTo(BigInteger.ZERO) == 0)                break;            for(int i = 0; i < 600; i ++)                if(f[i].compareTo(a) != -1 && f[i].compareTo(b) != 1)                    res ++;            System.out.println(res);        }    }}

C++

#include <map>#include <set>#include <list>#include <cmath>#include <ctime>#include <deque>#include <stack>#include <queue>#include <cctype>#include <cstdio>#include <string>#include <vector>#include <climits>#include <cstdlib>#include <cstring>#include <iostream>#include <algorithm>#define LL long long#define PI 3.1415926535897932626using namespace std;int gcd(int a, int b) {return a % b == 0 ? b : gcd(b, a % b);}const int numlen=110;struct bign {    int len, s[numlen];    bign() {        memset(s, 0, sizeof(s));        len = 1;    }    bign(int num) { *this = num; }    bign(const char *num) { *this = num; }    bign operator = (const int num) {        char s[numlen];        sprintf(s, "%d", num);        *this = s;        return *this;    }    bign operator = (const char *num) {        len = strlen(num);        while(len > 1 && num[0] == 0) num++, len--;        for(int i = 0;i < len; i++) s[i] = num[len-i-1] - 0;        return *this;    }    void deal() {        while(len > 1 && !s[len-1]) len--;    }    bign operator + (const bign &a) const {        bign ret;        ret.len = 0;        int top = max(len, a.len) , add = 0;        for(int i = 0;add || i < top; i++) {            int now = add;            if(i < len) now += s[i];            if(i < a.len)   now += a.s[i];            ret.s[ret.len++] = now%10;            add = now/10;        }        return ret;    }    bign operator - (const bign &a) const {        bign ret;        ret.len = 0;        int cal = 0;        for(int i = 0;i < len; i++) {            int now = s[i] - cal;            if(i < a.len)   now -= a.s[i];            if(now >= 0)    cal = 0;            else {                cal = 1; now += 10;            }            ret.s[ret.len++] = now;        }        ret.deal();        return ret;    }    bign operator * (const bign &a) const {        bign ret;        ret.len = len + a.len;        for(int i = 0;i < len; i++) {            for(int j = 0;j < a.len; j++)                ret.s[i+j] += s[i]*a.s[j];        }        for(int i = 0;i < ret.len; i++) {            ret.s[i+1] += ret.s[i]/10;            ret.s[i] %= 10;        }        ret.deal();        return ret;    }    bign operator * (const int num) {//        printf("num = %d\n", num);        bign ret;        ret.len = 0;        int bb = 0;        for(int i = 0;i < len; i++) {            int now = bb + s[i]*num;            ret.s[ret.len++] = now%10;            bb = now/10;        }        while(bb) {            ret.s[ret.len++] = bb % 10;            bb /= 10;        }        ret.deal();        return ret;    }    bign operator / (const bign &a) const {        bign ret, cur = 0;        ret.len = len;        for(int i = len-1;i >= 0; i--) {            cur = cur*10;            cur.s[0] = s[i];            while(cur >= a) {                cur -= a;                ret.s[i]++;            }        }        ret.deal();        return ret;    }    bign operator % (const bign &a) const {        bign b = *this / a;        return *this - b*a;    }    bign operator += (const bign &a) { *this = *this + a; return *this; }    bign operator -= (const bign &a) { *this = *this - a; return *this; }    bign operator *= (const bign &a) { *this = *this * a; return *this; }    bign operator /= (const bign &a) { *this = *this / a; return *this; }    bign operator %= (const bign &a) { *this = *this % a; return *this; }    bool operator < (const bign &a) const {        if(len != a.len)    return len < a.len;        for(int i = len-1;i >= 0; i--) if(s[i] != a.s[i])            return s[i] < a.s[i];        return false;    }    bool operator > (const bign &a) const  { return a < *this; }    bool operator <= (const bign &a) const { return !(*this > a); }    bool operator >= (const bign &a) const { return !(*this < a); }    bool operator == (const bign &a) const { return !(*this > a || *this < a); }    bool operator != (const bign &a) const { return *this > a || *this < a; }    string str() const {        string ret = "";        for(int i = 0;i < len; i++) ret = char(s[i] + 0) + ret;        return ret;    }};istream& operator >> (istream &in, bign &x) {    string s;    in >> s;    x = s.c_str();    return in;}ostream& operator << (ostream &out, const bign &x) {    out << x.str();    return out;}bign res[600];bign a,b;void init(){    res[1]="1";    res[2]="2";    for (int i=3;i<600;i++)        res[i]=res[i-1]+res[i-2];}int main(){    init();    while (cin>>a>>b)    {        if (a=="0" && b=="0") break;        int ans=0;        for (int i=1;i<600;i++)            if (res[i]>=a && res[i]<=b) ans++;        printf("%d\n",ans);    }    return 0;}

 

UVA 10183 How Many Fibs?