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HDOJ 1316 How Many Fibs?
JAVA大数....
How Many Fibs?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3906 Accepted Submission(s): 1545
Problem Description
Recall the definition of the Fibonacci numbers:
f1 := 1
f2 := 2
fn := fn-1 + fn-2 (n >= 3)
Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b].
f1 := 1
f2 := 2
fn := fn-1 + fn-2 (n >= 3)
Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b].
Input
The input contains several test cases. Each test case consists of two non-negative integer numbers a and b. Input is terminated by a = b = 0. Otherwise, a <= b <= 10^100. The numbers a and b are given with no superfluous leading zeros.
Output
For each test case output on a single line the number of Fibonacci numbers fi with a <= fi <= b.
Sample Input
10 100 1234567890 9876543210 0 0
Sample Output
5 4
Source
University of Ulm Local Contest 2000
import java.util.*; import java.math.*; import java.io.*; public class Main { public static void main(String[] args) { Scanner cin=new Scanner(System.in); final BigInteger maxlimit=BigInteger.TEN.pow(100); BigInteger[] fib=new BigInteger[500]; fib[0]=BigInteger.ONE; fib[1]=BigInteger.valueOf(2); for(int i=2;i<500;i++) { fib[i]=fib[i-1].add(fib[i-2]); } while(cin.hasNextBigInteger()) { BigInteger a=cin.nextBigInteger(); BigInteger b=cin.nextBigInteger(); if(a.compareTo(BigInteger.ZERO)==0&&b.compareTo(BigInteger.ZERO)==0) break; int ans=0; for(int i=0;i<500;i++) { if(fib[i].compareTo(a)>=0&&fib[i].compareTo(b)<=0) ans++; } System.out.println(ans); } } }
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