给定正整数N,统计1-N的连续整数中1的个数

int CountNumOf1(int digital)

{

int num = 0;

while(digital)

{

num += (digital % 10 == 1) ? 1: 0;

digital /= 10;

}

return num;

}

int CountTotalNumOf1(int N)

{

int sum=0;

printf("前N个连续数是:\n");

for(int i=1;i<=N;++i)

{

printf("%d ",i);

sum += CountNumOf1(i);

}

return sum;

}

int main(void)

{

int n;

        scanf("%d",&n);

printf("\n1的个数为:%2d\n",CountTotalNumOf1(n));

return 0;

}

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给定正整数N,统计1-N的连续整数中1的个数