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142. Linked List Cycle II
Given a linked list, return the node where the cycle begins. If there is no cycle, return null
.
Note: Do not modify the linked list.
Follow up:
Can you solve it without using extra space?
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution {10 public:11 ListNode *detectCycle(ListNode *head) {12 if(head == NULL || head->next == NULL){13 return NULL;14 }15 16 ListNode* slow = head;17 ListNode* fast = head;18 19 while(fast->next != NULL && fast->next->next != NULL){20 fast = fast->next->next;21 slow = slow->next;22 23 if(fast == slow){24 slow = head;25 26 while(slow != fast){27 slow = slow->next;28 fast = fast->next;29 }30 31 return slow;32 }33 }34 return NULL;35 }36 };
142. Linked List Cycle II
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