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ZOJ 2988 Conversions(数学啊)
题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1987
Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:
Type | Metric | English | equivalent |
Weight | 1.000 | kilograms | 2.2046 pounds |
Weight | 0.4536 | kilograms | 1.0000 pound |
Volume | 1.0000 | liter | 0.2642 gallons |
Volume | 3.7854 | liters | 1.0000 gallon |
Input
The first line of input contains a single integer N, (1 <= N <= 1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.
Output
For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.
Sample Input
5
1 kg
2 l
7 lb
3.5 g
0 l
Sample Output
1 2.2046 lb
2 0.5284 g
3 3.1752 kg
4 13.2489 l
5 0.0000 g
代码如下:
#include <cstdio> #include <cstring> int main() { int k = 0; double n; int t; char s[3]; scanf("%d",&t); while(t--) { scanf("%lf%s",&n,s); k++; printf("%d ",k); if(strcmp(s,"kg") == 0) { printf("%.4lf lb\n",n*2.2046); } else if(strcmp(s,"l") == 0) { printf("%.4lf g\n",n*0.2642); } else if(strcmp(s,"lb") == 0) { printf("%.4lf kg\n",n*0.4536); } else if(strcmp(s,"g") == 0) { printf("%.4lf l\n",n*3.7854); } } return 0; }
ZOJ 2988 Conversions(数学啊)