首页 > 代码库 > bzoj1111 [POI2007]四进制的天平Wag
bzoj1111 [POI2007]四进制的天平Wag
传送门:http://www.lydsy.com/JudgeOnline/problem.php?id=1111
【题解】
这题号注定单身。
转成四进制考虑
设f[i]表示从第i位往前的min,g[i]表示从第i位往前(第i位借1位)往前的min
那么转移随便做了。。
md还要取模,没看这个wa了3发
# include <stdio.h> # include <string.h> # include <iostream> # include <algorithm> // # include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef unsigned long long ull; const int M = 8e3 + 10; const int mod = 1e9; # define RG register # define ST static int a[M], b[M]; int n[M], N = 0; char str[M]; struct pa { int x, num; pa() {} pa(int x, int num) : x(x), num(num) {} }f[M], g[M]; inline pa cmin(pa a, pa b, int c) { b.x += c; if(b.x < a.x) a = b; else if(b.x == a.x) (a.num += b.num) %= mod; return a; } inline int div(int *a) { b[0] = 0; int x = 0; for (int i=1; i<=a[0]; ++i) { b[++b[0]] = (x*10 + a[i])/4; x = (x*10 + a[i])%4; } int len = 0; while(b[len+1] == 0 && len < a[0]) ++len; // printf("%d\n", b[0]); system("pause"); a[0] = 0; for (int i=len+1; i<=b[0]; ++i) a[++a[0]] = b[i]; // cout << endl; // cout << "mod res = " << x << endl; return x; } inline void transform() { while(a[0] != 0) n[++N] = div(a); } int main() { scanf("%s", str); int x = 0; a[0] = 0; for (int i=0; str[i]; ++i) { ++a[0]; a[a[0]] = str[i] - ‘0‘; } transform(); // cout << N << endl; // for (int i=1; i<=N; ++i) cout << n[i]; // cout << endl; for (int i=N+1; i; --i) f[i] = pa(1e9, 0), g[i] = pa(1e9, 0); // 从第i位往前,从第i位(这一位借位了)往前 f[N+1] = pa(0, 1), g[N+1] = pa(1, 1); for (int i=N; i; --i) { if(n[i] == 0) { f[i] = cmin(f[i], f[i+1], 0); f[i] = cmin(f[i], g[i+1], 4); g[i] = cmin(g[i], f[i+1], 1); g[i] = cmin(g[i], g[i+1], 3); } else if(n[i] == 1) { f[i] = cmin(f[i], f[i+1], 1); f[i] = cmin(f[i], g[i+1], 3); g[i] = cmin(g[i], f[i+1], 2); g[i] = cmin(g[i], g[i+1], 2); } else if(n[i] == 2) { f[i] = cmin(f[i], f[i+1], 2); f[i] = cmin(f[i], g[i+1], 2); g[i] = cmin(g[i], f[i+1], 3); g[i] = cmin(g[i], g[i+1], 1); } else { f[i] = cmin(f[i], f[i+1], 3); f[i] = cmin(f[i], g[i+1], 1); g[i] = cmin(g[i], f[i+1], 4); g[i] = cmin(g[i], g[i+1], 0); } } cout << f[1].num << endl; return 0; }
bzoj1111 [POI2007]四进制的天平Wag
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