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To the Max
To the Max
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Time Limit: 1 Second Memory Limit: 32768 KB
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Problem
Given a two-dimensional array of positive and negative integers, a sub-rectangle is any contiguous sub-array of size 1 x 1 or greater located within the whole array. The sum of a rectangle is the sum of all the elements in that rectangle. In this problem the sub-rectangle with the largest sum is referred to as the maximal sub-rectangle.
As an example, the maximal sub-rectangle of the array:
0 -2 -7 0
9 2 -6 2
-4 1 -4 1
-1 8 0 -2
is in the lower left corner:
9 2
-4 1
-1 8
and has a sum of 15.
The input consists of an N x N array of integers. The input begins with a single positive integer N on a line by itself, indicating the size of the square two-dimensional array. This is followed by N 2 integers separated by whitespace (spaces and newlines). These are the N 2 integers of the array, presented in row-major order. That is, all numbers in the first row, left to right, then all numbers in the second row, left to right, etc. N may be as large as 100. The numbers in the array will be in the range [-127,127].
Output
Output the sum of the maximal sub-rectangle.
Example Input
4
0 -2 -7 0 9 2 -6 2
-4 1 -4 1 -1
8 0 -2
Output
15
1 #include<stdio.h> 2 #include<string.h> 3 #define MAXN 105 4 int main() 5 { 6 //freopen("a.txt","r",stdin); 7 int i,j,k,n,t,sum,max; 8 int a[MAXN][MAXN]; 9 while (scanf("%d",&n)!=EOF)10 {11 memset(a,0,sizeof(a));12 for (i=1;i<=n;++i)13 {14 for (j=1;j<=n;++j)15 {16 scanf("%d",&t);17 a[i][j]=a[i-1][j]+t;18 }19 }20 max=0;21 for (i=1;i<=n;++i)22 {23 for (j=i;j<=n;++j)24 {25 sum=0;26 for (k=1;k<=n;++k)27 {28 t=a[j][k]-a[i-1][k];29 sum+=t;30 if (sum<0) sum=0;31 if (sum>max) max=sum;32 }33 }34 }35 printf("%d\n",max);36 }37 return 0;38 }
To the Max