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HDU1429 - 胜利大逃亡(续)
与上一道题:HDU1885 - Key Task基本没什么两样
1 #include <iostream> 2 #include <cstdio> 3 #include <algorithm> 4 #include <cstring> 5 #include <string> 6 #include <queue> 7 #include <cctype> 8 using namespace std; 9 const int maxn = 25; 10 int n, m, fail; 11 char G[maxn][maxn]; 12 int vis[maxn][maxn][2000]; 13 const int dr[] = {-1, 0, 1, 0}; 14 const int dc[] = { 0, 1, 0,-1}; 15 16 struct Node 17 { 18 int r, c, key, step; 19 Node(int r = 0, int c = 0, int key = 0, int step = 0):r(r), c(c), key(key), step(step){} 20 }; 21 22 bool isInside(int r, int c) 23 { 24 if(r > 0 && r <= n && c > 0 && c <= m && G[r][c] != ‘*‘) 25 return true; 26 else 27 return false; 28 } 29 30 void bfs(int rr, int cc) 31 { 32 queue<Node> q; 33 memset(vis, 0, sizeof vis); 34 Node node(rr, cc, 0, 0); 35 q.push(node); 36 while(!q.empty()) { 37 Node u = q.front(); 38 q.pop(); 39 if(G[u.r][u.c] == ‘^‘) { 40 if(u.step < fail) 41 printf("%d\n", u.step); 42 else 43 printf("-1\n"); 44 return; 45 } 46 for(int i = 0; i < 4; i++) { 47 Node v(u.r + dr[i], u.c + dc[i], u.key, u.step+1); 48 if(isInside(v.r, v.c)) { 49 if(islower(G[v.r][v.c])) { 50 int k = G[v.r][v.c] - ‘a‘; 51 if((v.key & (1 << k)) == 0) { 52 v.key += (1 << k); 53 } 54 if(!vis[v.r][v.c][v.key]) { 55 vis[v.r][v.c][v.key] = 1; 56 q.push(v); 57 } 58 } 59 else if(isupper(G[v.r][v.c])) { 60 int k = G[v.r][v.c] - ‘A‘; 61 if(v.key & (1 << k) && !vis[v.r][v.c][v.key]) { 62 vis[v.r][v.c][v.key] = 1; 63 q.push(v); 64 } 65 } 66 else { 67 if(!vis[v.r][v.c][v.key]) { 68 vis[v.r][v.c][v.key] = 1; 69 q.push(v); 70 } 71 } 72 } 73 } 74 } 75 printf("-1\n"); 76 } 77 int main() 78 { 79 // freopen("in.txt", "r", stdin); 80 while(scanf("%d %d %d", &n, &m, &fail) != EOF) { 81 memset(G, ‘*‘, sizeof G); 82 int x, y; 83 for(int i = 1; i <= n; i++) { 84 scanf("%s", G[i]+1); 85 G[i][m+1] = ‘*‘; 86 G[i][m+2] = ‘\0‘; 87 if(strchr(G[i], ‘@‘)) { 88 x = i; 89 y = strchr(G[i], ‘@‘) - *G - i*25; 90 } 91 } 92 //printf("%d %d\n", x, y); 93 bfs(x, y); 94 } 95 return 0; 96 }
HDU1429 - 胜利大逃亡(续)
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