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今日已更新 2618 篇代码解决方案
题意：Description 现在请求你维护一个数列，要求提供以下两种操作：1、 查询操作。语法：Q L 功能：查询当前数列中末尾L个数中的最大的数，并输出这个数的值
https://www.u72.net/daima/zwfe.html - 2024-08-12 15:15:25 - 代码库题目链接：http://www.spoj.com/problems/QTREE/en/照着集训队论文敲的&hellip;万幸树剖部分没写错&hellip; 1 #include <algorithm> 2 #include <iost
https://www.u72.net/daima/n7bc.html - 2024-08-12 01:19:55 - 代码库Description C国的死对头A国这段时间正在进行军事演习，所以C国间谍头子Derek和他手下Tidy又开始忙乎了。A国在海岸线沿直线布置了N个工兵营 地,Derek和T
https://www.u72.net/daima/hu19.html - 2024-08-13 10:49:34 - 代码库链接poj3667的加强版 当时的题解这里只不过对于女神需要另开算，DS的占用的时间不加在女神身上，女神的时间都要加，清空的时候也都要算。 1 #include <iost
https://www.u72.net/daima/h8me.html - 2024-07-06 10:25:44 - 代码库敌兵布阵Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 78528 Accepted Submissio
https://www.u72.net/daima/hkrw.html - 2024-08-13 05:15:51 - 代码库敌兵布阵Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 78691 Accepted Submissio
https://www.u72.net/daima/h5wk.html - 2024-08-13 17:34:30 - 代码库DescriptionThe citizens of Bytetown, AB, could not stand that the candidates in the mayoral election campaign have been placing their electo
https://www.u72.net/daima/crxz.html - 2024-07-10 23:26:14 - 代码库题目描述：长度为L个单位的画板，有T种不同的颜料，现要求按序做O个操作，操作分两种：1.“C A B C”,即将A到B之间的区域涂上颜色C2.“P A B”，查询[A，B]区域
https://www.u72.net/daima/f387.html - 2024-07-10 07:38:09 - 代码库DescriptionYou have N integers, A1,A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given n
https://www.u72.net/daima/whxx.html - 2024-07-15 20:28:09 - 代码库A Simple Problem with IntegersTime Limit: 5000MS Memory Limit: 131072KTotal Submissions: 60441 Accepted: 18421Case Time Limit: 2000MSDescrip
https://www.u72.net/daima/wh0x.html - 2024-07-15 20:29:55 - 代码库题目链接题意：有N个人排队，给出各个人想插队的位置和标识，要求输出最后的序列。分析：因为之前的序列会因为插队而变化，如果直接算时间复杂度很高，所以可以用
https://www.u72.net/daima/whua.html - 2024-07-15 20:21:00 - 代码库Balanced LineupTime Limit: 5000MS Memory Limit: 65536KTotal Submissions: 32778 Accepted: 15425Case Time Limit: 2000MSDescriptionFor the dail
https://www.u72.net/daima/rrda.html - 2024-07-11 23:08:21 - 代码库题目大意：有一排标号1-N的房间。操作一：询问是不是有连续长度为a的空房间,有的话住进最左边（占用a个房间）操作二：将[a,a+b-1]的房间清空（腾出b个房间）思路
https://www.u72.net/daima/w1hs.html - 2024-07-16 07:20:07 - 代码库解题报告题意：略思路：单点替换，区间最&#20540;#include <iostream>#include <cstring>#include <cstdio>#define inf 99999999using namespace std;i
https://www.u72.net/daima/w3hx.html - 2024-07-16 09:03:29 - 代码库Problem Description世界上上最远的距离不是相隔天涯海角而是我在你面前可你却不知道我爱你 ―― 张小娴前段日子，枫冰叶子给Wiske
https://www.u72.net/daima/w199.html - 2024-07-16 08:02:32 - 代码库Just a HookTime Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 17124 Accepted Submis
https://www.u72.net/daima/w4n3.html - 2024-07-16 09:50:43 - 代码库解题报告题意：略思路：单点更新，区间乘积。#include <cstdio>#include <iostream>#include <cstring>#define LL long longusing namespace std;LL mu
https://www.u72.net/daima/w4zn.html - 2024-07-16 09:51:29 - 代码库题目：hdoj1166分析：题意很清晰，就是让你给某个点又增加或者减少x个，然后求某一段有多少个，我是用一个father数组保存叶子节点的编号，然后直接从当前节点开始
https://www.u72.net/daima/s4b4.html - 2024-07-13 10:03:09 - 代码库Luck and LoveTime Limit: 10000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5282 Accepted Su
https://www.u72.net/daima/wr8d.html - 2024-07-16 02:05:57 - 代码库维护二维矩阵。q x1, y1, x2, y2 : 查询x1<=x<=x2, y1<=y<=y2的&#26684;子(x,y)的最大&#20540;和最小&#20540;。c x, y, v: 修改(x,y) = v。
https://www.u72.net/daima/wc3d.html - 2024-07-16 01:04:43 - 代码库