首页 > 代码库 > UVA 10359 Tiling
UVA 10359 Tiling
考虑最左边一列和最左边两列分别可以一个纵方块;2个横方块+2*2;
则f[i]=f[i-1]+2f[i-2];
#include <map>#include <set>#include <list>#include <cmath>#include <ctime>#include <deque>#include <stack>#include <queue>#include <cctype>#include <cstdio>#include <string>#include <vector>#include <climits>#include <cstdlib>#include <cstring>#include <iostream>#include <algorithm>#define LL long long#define PI 3.1415926535897932626using namespace std;int gcd(int a, int b) {return a % b == 0 ? b : gcd(b, a % b);}const int numlen=110;struct bign { int len, s[numlen]; bign() { memset(s, 0, sizeof(s)); len = 1; } bign(int num) { *this = num; } bign(const char *num) { *this = num; } bign operator = (const int num) { char s[numlen]; sprintf(s, "%d", num); *this = s; return *this; } bign operator = (const char *num) { len = strlen(num); while(len > 1 && num[0] == ‘0‘) num++, len--; for(int i = 0;i < len; i++) s[i] = num[len-i-1] - ‘0‘; return *this; } void deal() { while(len > 1 && !s[len-1]) len--; } bign operator + (const bign &a) const { bign ret; ret.len = 0; int top = max(len, a.len) , add = 0; for(int i = 0;add || i < top; i++) { int now = add; if(i < len) now += s[i]; if(i < a.len) now += a.s[i]; ret.s[ret.len++] = now%10; add = now/10; } return ret; } bign operator - (const bign &a) const { bign ret; ret.len = 0; int cal = 0; for(int i = 0;i < len; i++) { int now = s[i] - cal; if(i < a.len) now -= a.s[i]; if(now >= 0) cal = 0; else { cal = 1; now += 10; } ret.s[ret.len++] = now; } ret.deal(); return ret; } bign operator * (const bign &a) const { bign ret; ret.len = len + a.len; for(int i = 0;i < len; i++) { for(int j = 0;j < a.len; j++) ret.s[i+j] += s[i]*a.s[j]; } for(int i = 0;i < ret.len; i++) { ret.s[i+1] += ret.s[i]/10; ret.s[i] %= 10; } ret.deal(); return ret; } bign operator * (const int num) {// printf("num = %d\n", num); bign ret; ret.len = 0; int bb = 0; for(int i = 0;i < len; i++) { int now = bb + s[i]*num; ret.s[ret.len++] = now%10; bb = now/10; } while(bb) { ret.s[ret.len++] = bb % 10; bb /= 10; } ret.deal(); return ret; } bign operator / (const bign &a) const { bign ret, cur = 0; ret.len = len; for(int i = len-1;i >= 0; i--) { cur = cur*10; cur.s[0] = s[i]; while(cur >= a) { cur -= a; ret.s[i]++; } } ret.deal(); return ret; } bign operator % (const bign &a) const { bign b = *this / a; return *this - b*a; } bign operator += (const bign &a) { *this = *this + a; return *this; } bign operator -= (const bign &a) { *this = *this - a; return *this; } bign operator *= (const bign &a) { *this = *this * a; return *this; } bign operator /= (const bign &a) { *this = *this / a; return *this; } bign operator %= (const bign &a) { *this = *this % a; return *this; } bool operator < (const bign &a) const { if(len != a.len) return len < a.len; for(int i = len-1;i >= 0; i--) if(s[i] != a.s[i]) return s[i] < a.s[i]; return false; } bool operator > (const bign &a) const { return a < *this; } bool operator <= (const bign &a) const { return !(*this > a); } bool operator >= (const bign &a) const { return !(*this < a); } bool operator == (const bign &a) const { return !(*this > a || *this < a); } bool operator != (const bign &a) const { return *this > a || *this < a; } string str() const { string ret = ""; for(int i = 0;i < len; i++) ret = char(s[i] + ‘0‘) + ret; return ret; }};istream& operator >> (istream &in, bign &x) { string s; in >> s; x = s.c_str(); return in;}ostream& operator << (ostream &out, const bign &x) { out << x.str(); return out;}bign f[260];void init(){ f[0]=1; f[1]=1;f[2]=3; for (int i=3;i<255;i++) { f[i]=f[i-1]+f[i-2]; f[i]+=f[i-2]; }}char a[numlen];int main(){ init(); int b; while (cin>>b) { cout<<f[b]<<endl; } return 0;}
UVA 10359 Tiling
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。