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HDU 1028 Ignatius and the Princess III 母函数

其实这题是水题,DP随便搞一下就能求,但是第一次写母函数,所以找了道水题做好理解些~_~

 

#include <cstdio>#include <cstring>#include <cmath>#include <algorithm>#include <climits>#include <string>#include <iostream>#include <map>#include <cstdlib>#include <list>#include <set>#include <queue>#include <stack>using namespace std;typedef long long LL;const int maxn = 125;int c1[maxn],c2[maxn];int main() {    int n;    while(scanf("%d",&n) == 1) {        //用第一个多项式初始化        for(int i = 0;i <= n;i++) {            c1[i] = 1; c2[i] = 0;        }        //第i个多项式        for(int i = 2;i <= n;i++) {            //第i个多项式中的第j项            for(int j = 0;j <= n;j += i) {                //依次累加                for(int k = 0;k + j <= n;k++) {                    c2[k + j] += c1[k];                }            }            memcpy(c1,c2,sizeof(c1));            memset(c2,0,sizeof(c2));        }        printf("%d\n",c1[n]);    }    return 0;}