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URAL 2018 The Debut Album (DP)
题意:给出n长度的数列,其实1的连续个数不超过a,2的连续个数不超过b。
析:dp[i][j][k] 表示前 i 个数,以 j 结尾,并且连续了k个长度,要用滚动数组,要不然MLE。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <map> #include <cctype> #include <cmath> #include <stack> #include <sstream> #define debug() puts("++++"); #define gcd(a, b) __gcd(a, b) #define lson l,m,rt<<1 #define rson m+1,r,rt<<1|1 #define freopenr freopen("in.txt", "r", stdin) #define freopenw freopen("out.txt", "w", stdout) using namespace std; typedef long long LL; typedef unsigned long long ULL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const LL LNF = 1e16; const double inf = 0x3f3f3f3f3f3f; const double PI = acos(-1.0); const double eps = 1e-8; const int maxn = 1e5 + 10; const int mod = 1e9 + 7; const int dr[] = {-1, 0, 1, 0}; const int dc[] = {0, 1, 0, -1}; const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"}; int n, m; const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m; } LL dp[2][2][310]; int main(){ int a, b; cin >> n >> a >> b; dp[0][0][1] = dp[0][1][1] = 1; int cnt = 1; LL sum1 = 1, sum2 = 1; for(int i = 1; i < n; ++i, cnt ^= 1){ dp[cnt][0][1] = sum1; dp[cnt][1][1] = sum2; swap(sum1, sum2); for(int j = 2; j <= a; ++j){ dp[cnt][0][j] = dp[cnt^1][0][j-1]; sum2 = (sum2 + dp[cnt][0][j]) % mod; } for(int j = 2; j <= b; ++j){ dp[cnt][1][j] = dp[cnt^1][1][j-1]; sum1 = (sum1 + dp[cnt][1][j]) % mod; } } LL ans = (sum1 + sum2) % mod; cout << ans << endl; return 0; }
URAL 2018 The Debut Album (DP)
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