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[再寄小读者之数学篇](2014-05-27 积分估计)

试证: kπ0|sinx|xdx>2πlnk+12<script id="MathJax-Element-1" type="math/tex">\dps{\int_0^{k\pi} \cfrac{|\sin x|}{x}\rd x> \cfrac{2}{\pi}\ln\cfrac{k+1}{2}}</script>.