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265656464

$(12苏大四)$设$f\left( x \right) \in {C^1}\left( { - \infty , + \infty } \right)$,且

+?[f(x)2+f2(x)]dx=1
<script id="MathJax-Element-1" type="math/tex; mode=display">\int_{ - \infty }^{ + \infty } {\left[ {f{{\left( x \right)}^2} + {{f‘}^2}\left( x \right)} \right]dx} = 1</script>
证明:$(1)$$\lim \limits_{x \to \begin{array}{*{20}{c}}
\infty \end{array}} f\left( x \right) = 0$

$(2)$对任意$x \in \left( { - \infty , + \infty } \right)$,有$\left| {f\left( x \right)} \right| < \frac{{\sqrt 2 }}{2}$

$(08华师七)$设$u\left( x \right)$在$\left[ {0, + \infty } \right)$上连续可微,且

+0(|u(x)|2+u(x)2)dx<+
<script id="MathJax-Element-2" type="math/tex; mode=display">\int_0^{ + \infty } {\left( {{{\left| {u\left( x \right)} \right|}^2} + {{\left| {u‘\left( x \right)} \right|}^2}} \right)dx} < + \infty </script>证明:

$(1)$存在$\left[ {0, + \infty } \right)$上子列$\left\{ {{x_n}} \right\}$,使得${x_n} \to \infty $,且$u\left( {{x_n}} \right) \to 0\left( {n \to \infty } \right)$

$(2)$存在常数$C>0$,使得

Supx[0,+)|u(x)|C(+0|u(x)|2+u(x)2dx)12
<script id="MathJax-Element-3" type="math/tex; mode=display">\mathop {Sup}\limits_{x \in \left[ {0, + \infty } \right)} \left| {u\left( x \right)} \right| \le C{\left( {\int_0^{ + \infty } {{{\left| {u\left( x \right)} \right|}^2} + {{\left| {u‘\left( x \right)} \right|}^2}dx} } \right)^{\frac{1}{2}}}</script>