首页 > 代码库 > POJ 1598 find the most comfortable road
POJ 1598 find the most comfortable road
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1598
思路:通过思路转换,可以看出是求两个点之间最大边权值与最小边权值之差最小的。克鲁斯卡尔算法枚举之~
#include <iostream>#include <cstdio>#include <cmath>#include <cstring>#include <algorithm>#include <queue>#include <stack>#include <vector>#include <cstdlib>#include <string>using namespace std;int n,m;int f[210];struct node{ int u,v; int w;}map[1020];int getf(int a){ if(f[a] == a) return a; f[a] = getf(f[a]); return f[a];}void merge(int a, int b){ int x = getf(a); int y = getf(b); if(x!=y) f[y] = x;}void init(){ for(int i=1; i<=n; i++) { f[i] = i; }}bool cmp(node a, node b){ return a.w < b.w;}int solve(int start, int end){ int maxn = -1; int minn = 999999999; sort(map,map+m,cmp); int res = 999999999; for(int k = 0; k < m; k++) { init(); maxn = -1; minn = 999999999; for(int i = k; i < m; i++) { if(getf(map[i].u) != getf(map[i].v)) { merge(map[i].u, map[i].v); maxn = max(maxn, map[i].w); minn = min(minn, map[i].w); } if(getf(start) == getf(end)) { res = min(maxn - minn, res); break; } } } if(res == 999999999) res = -1; return res;}int main(){ int q; while(scanf("%d %d", &n, &m)!=EOF) { for(int i=0; i<m; i++) { scanf("%d %d %d", &map[i].u, &map[i].v, &map[i].w); } scanf("%d", &q); int s[20][2]; for(int i=1; i<=q; i++) { init(); scanf("%d %d", &s[i][0], &s[i][1]); printf("%d\n", solve(s[i][0],s[i][1])); } } return 0;}
POJ 1598 find the most comfortable road
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。